(20b^4/5)/(4b^1/2)

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Solution for (20b^4/5)/(4b^1/2) equation: 


D( b )

(4*b^1)/2 = 0

(4*b^1)/2 = 0

(4*b^1)/2 = 0

(4*b)/2 = 0

2*b = 0 // : 2

b = 0

b in (-oo:0) U (0:+oo)

((20*b^4)/5)/((4*b^1)/2) = 0

((20*b^4)/5)/((4*b)/2) = 0

2*b^3 = 0 // : 2

b^3 = 0

b = 0

b in { 0} 

b belongs to the empty set

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